(no subject)
Jan. 16th, 2007 09:31 pmSo, the question came up nexusly on TIM about the weight of a cubic meter of pure gold.
1 m = 100 cm
1 m^3 = 100 cm x 100 cm x 100 cm = 1,000,000 cm^3 = 1.0 x 10^6 cm^3
Density of pure gold = 19.3 g/cm^3
Mass = Density x Volume = 19.3 g/cm^3 x 1.0 x 10^6 cm^3
= 19.3 x 10^6 g (or 1.93 x 10^7 g, if you're being picky)
= 19.3 x 10^3 kg (or 1.93 x 10^4 kg, if you're still being picky)
Conversion of mass (in kg) to weight (in pounds) is (Mass in kg) x (2.20 pounds/kg), so:
(19.3 x 10^3 kg) x (2.20 pounds/kg) = 42,460 pounds (if we're ignoring significant digits)
So, if my calculations are correct, it's about 21 tons. It seems high to me, but then I've been teaching division by decimals all day. :)
1 m = 100 cm
1 m^3 = 100 cm x 100 cm x 100 cm = 1,000,000 cm^3 = 1.0 x 10^6 cm^3
Density of pure gold = 19.3 g/cm^3
Mass = Density x Volume = 19.3 g/cm^3 x 1.0 x 10^6 cm^3
= 19.3 x 10^6 g (or 1.93 x 10^7 g, if you're being picky)
= 19.3 x 10^3 kg (or 1.93 x 10^4 kg, if you're still being picky)
Conversion of mass (in kg) to weight (in pounds) is (Mass in kg) x (2.20 pounds/kg), so:
(19.3 x 10^3 kg) x (2.20 pounds/kg) = 42,460 pounds (if we're ignoring significant digits)
So, if my calculations are correct, it's about 21 tons. It seems high to me, but then I've been teaching division by decimals all day. :)