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[personal profile] bigmeanie
So, the question came up nexusly on TIM about the weight of a cubic meter of pure gold.

1 m = 100 cm
1 m^3 = 100 cm x 100 cm x 100 cm = 1,000,000 cm^3 = 1.0 x 10^6 cm^3

Density of pure gold = 19.3 g/cm^3

Mass = Density x Volume = 19.3 g/cm^3 x 1.0 x 10^6 cm^3

= 19.3 x 10^6 g (or 1.93 x 10^7 g, if you're being picky)
= 19.3 x 10^3 kg (or 1.93 x 10^4 kg, if you're still being picky)

Conversion of mass (in kg) to weight (in pounds) is (Mass in kg) x (2.20 pounds/kg), so:
(19.3 x 10^3 kg) x (2.20 pounds/kg) = 42,460 pounds (if we're ignoring significant digits)

So, if my calculations are correct, it's about 21 tons. It seems high to me, but then I've been teaching division by decimals all day. :)

Date: 2007-01-17 12:45 pm (UTC)
From: [identity profile] daeghnao.livejournal.com
Looks good to me. Adding in the units makes it a lot easier to follow along and see that all the multiplications and divisions are the right way round.

Also, if you think about the density of gold = 19.3g/cm^3, that's approximately 7/10oz per cc, giving a bit under 700000oz in a cubic metre, or a bit under 43750lb (obviously lots of rounding error got multiplied up here). But it corroborates your more accurate calculation and helps give a feel for the problem.

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